Find two consecutive odd integers such that the square of the first added to 3 times the second, is 24. Part a: Define the variables. Part b: Set up an equations that can be solved to find the integers. Part c: Find the integers.

Given:

There are two consecutive odd integers such that the square of the first added to 3 times the second, is 24.

To find:

Part a: Define the variables.

Part b: Set up an equations that can be solved to find the integers.

Part c: Find the integers.

Solution:

Part a:

Let x be the first odd integers. Then next consecutive odd integer is , because the difference between two consecutive odd integers is 2.

Part b:

Square of first odd integers =

Three times of second odd integers =

It is given that the sum of square of first odd integers and three times of second odd integers is 24. So, the required equation is:

Part c:

The equation is:

It can be written as:

Splitting the middle term, we get

-6 is not an odd integer, so and the first odd integer is 3.

Second odd integer =

                                  =

                                  =

Therefore, the two consecutive odd integers are 3 and 5.

a = 11 : 4

b = 38

c = 1 for every 6

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.