27 may 2021 A box has 14 identical balls, three of which are blue, then two balls are drawn at random from the box, one after the other without replacement. Calculate the probability that
(i) the two balls are both blue
(ii) Atleast one ball drawn is blue.​

3/91 ; 36/91

Step-by-step explanation:

1) favourable event/ total possibilities * favourable event/ new total possibilities

3/14 * 2/13 = 3/91

2) it is simplier calculate the probability of the opposite event (no balls are blue)

11/14 * 10/13 = 55/91

91 - 55 = 36

final answer 36/91

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this