Boyle's law is :
p1 v1 = p2 v2

what happens to the pressure of a container if the volume is doubled and the temperature is kept the same?

- impossible to determine with the info provided

- the pressure will increase

- the pressure will decrease

- the pressure will stay the same

- the pressure will decrease

(volume is doubled ,the pressure reduced by half).

Step-by-step explanation:

P_{1}V_{1} =P_{2}V_{2}.

This equation shows that, as volume increases, the pressure of the gas decreases in proportion.

Similarly, as volume decreases, the pressure of the gas increases.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: