A rectangular field is nine times as long as it is wide. If the perimeter of the field is 1700 feet, what are the dimensions of the field?

A) Write an equation you can use to answer the given question. Let w be the width of the field. Do not
solve the equation yet.

The equation is
X (Make sure you use the correct variable.)

B) Use your equation to find the dimensions of the field.

The width of the field is
x feet.
The length of the field is
x feet.

I. L = 10.35 feet

II. W = 93.15 feet.

Step-by-step explanation:

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data;

Perimeter of rectangular field = 1700 feet

Translating the word problem into an algebraic expression, we have;

W = 9L

Mathematically, the formula for the perimeter of a rectangle is;

P = 2(L + W)

A. To write an equation;

X = P = 2(L + W)

B. To find the dimensions of the field;

207 = 2(L + 9L)

207 = 2L + 18L

207 = 20L

L = 207/20

L = 10.35 feet

To find the weight;

W = 9L

W = 9 * 10.35

W = 93.15 feet.

Therefore, the width of the field is

93.15 feet and the length of the field is

10.35 feet.

x = 12

y = 15

step-by-step explanation:

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.