An algebra 2 test has 5 multiple choice questions with four choices with one correct answer each. If we just randomly guess on each of the 5 questions, what is the probability that you get at least 1 question correct

0.7627

Step-by-step explanation:

This is a binomial probability problem

Given :

Number of trials, n = 5

p = number of correct option / total options = 1/4 = 0.25

q = 1 - p = 1 - 0.25 = 0.75

Using the binomial probability relation :

P(x = x) = nCx * p^x * q^(n-x)

Getting atleast 1 correct :

P(x ≥ 1) = p(x = 1) + p(x = 2) + p(x = 3) + p(x =4) + p(x = 5)

P(x =1) = 5C1 * 0.25^1 * 0.75^4 = 0.3955

P(x =2) = 5C2 * 0.25^2 * 0.75^3 = 0.2637

P(x =3) = 5C3 * 0.25^3 * 0.75^2 = 0.0879

P(x =4) = 5C4 * 0.25^4 * 0.75^5 = 0.0146

P(x =5) = 5C5 * 0.25^5 * 0.75^0 = 0.0009

P(x ≥ 1) = 0.3955 + 0.2637 + 0.0879 + 0.0146 + 0.0009 = 0.7627

P(x ≥ 1) = 0.7627

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.