Two times a number minus four times another number is ten, and four times the first number minus four times the second number results in four. What are the two
numbers? Let the first number be x. Iand the second number be y.

-3 and -4

Step-by-step explanation:

x = 1st number

y = 2nd number

2x-4y=10

4x-4y=4

distribute first equation by -2 to eliminate x-values:

 -4x + 8y = -20

+ 4x - 4y = 4

4y = -16

y = -4

solve for 'x':

2x - 4(-4) = 10

2x + 16 = 10

2x = -6

x = -3

if this is really you s much. i only have 3 points left and i have 2 questions to ask

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."