two teams play a series of games, wher both teams have an equal probability of winning each game. its a best- of-five series, so the frist team to win three games is the winner. what is the probability that the series lasts five games

0.375

Step-by-step explanation:

With equal probability, hence

p for both teams = 0.5

First team to win three games win, probability that series lasts 5 games :

This means after 4 games each of the teams must have won 2 each ; and the series decider will be on the 5th game :

Each team winning two games and any of the teams could be the eventual winner :

From binomial relation :

P(x = x) = nCx * p^x * q^(n-x)

q = 1 - p = 0.5

Team A :

Winning any 2 from 4 and winning the 5th

(4C2 * 0.5^2 * 0.5^2) * 0.5

0.375 * 0.5 = 0.1875

Team B :

(4C2 * 0.5^2 * 0.5^2) * 0.5

0.375 * 0.5 = 0.1875

Hence, the probability that series lasts five games is :

[4C2*0.5^2*0.5^2)*0.5]+[4C2*0.5^2*0.5^2)*0.5]

0.1875 + 0.1875

= 0.375

2x^2+5x+17

your welcome. : )

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!