I need help find the area of the small sector
8 and 40
area=m2
(round to the neerest 100)

22.33 m²

Step-by-step explanation:

From the question given above, the following data were obtained:

Radius (r) = 8 m

Angle sustained (θ) = 40°

Pi (π) = 3.14

Area of small sector (A) =?

The area of the small sector can be obtained as illustrated below:

A = θ/360 × πr²

A = 40/360 × 3.14 × 8²

A = 40/360 × 3.14 × 64

A = 22.33 m²

Therefore, the area of the small sector is 22.33 m²

yes

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb