A sphere has a radius of 6 meters. A second sphere has a radius of 3 meters. What is the difference of the volumes of the spheres?

The difference between the volume of the two spheres is 791.6m^3.

Step-by-step explanation:

V = 4(pi)(r^3/3)

Sphere 1:

V = 4(pi)(6^3/3)

Solve.

V = 4(pi)(216/3)

V = 4(pi)(72)

V = 4(226.2)

V = (904.8)

Sphere 1 Volume: 904.8m^3

Sphere 2:

V = 4(pi)(3^3/3)

V = 4(pi)(27/3)

V = 4(pi)(9)

V = 4(28.3)

V = 113.2

Sphere 2 Volume: 113.2m^3

Subtract.

904.8 - 113.2 = 791.6

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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