g(x) = x2 + 3x + 40
Mathematics, 27.05.2021 23:10 amandapill
Which function has real zeros at x = –8 and x = 5?
g(x) = x2 + 3x – 40
g(x) = x2 + 3x + 40
g(x) = x2 + 14x – 40
g(x) = x2 + 14x + 40
Answers: 1
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Consider this expression and the steps to evaluate it. 4^5(−2)^9/4^8(−2)^3 1. apply the quotient of powers: (−2)^a/4^b 2. evaluate powers: c/d select the value of each variable. a = _ b = _ c = _ d = _
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Which function has real zeros at x = –8 and x = 5?
g(x) = x2 + 3x – 40
g(x) = x2 + 3x + 40
g(x) = x2 + 3x + 40
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