A) Select the equation that has a y-intercept value of 3 A: y = (x + 1)(x – 3) B: y = x² – 9
C: y = 3x(x – 3)
D: y = (x + 1)(x + 3)

D

Step-by-step explanation:

Given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the y- intercept is the value of the constant term c

A

y = (x + 1)(x - 3)

  = x² - 2x - 3 ← y- intercept = - 3

B

y = x² - 9 ← y- intercept = - 9

C

y = 3x(x - 3)

  = 3x² - 9x ← y- intercept = 0

D

y = (x + 1)(x + 3)

  = x² + 4x + 3 ← with y- intercept 3

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions