What are the roots of the equation x2
12x + 72 = 0 in simplest a + bi form?

(x + -6)(x + -6) = -36

Step-by-step explanation:

Simplifying

x2 + -12x + 72 = 0

Reorder the terms:

72 + -12x + x2 = 0

Solving

72 + -12x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-72' to each side of the equation.

72 + -12x + -72 + x2 = 0 + -72

Reorder the terms:

72 + -72 + -12x + x2 = 0 + -72

Combine like terms: 72 + -72 = 0

0 + -12x + x2 = 0 + -72

-12x + x2 = 0 + -72

Combine like terms: 0 + -72 = -72

-12x + x2 = -72

The x term is -12x.  Take half its coefficient (-6).

Square it (36) and add it to both sides.

Add '36' to each side of the equation.

-12x + 36 + x2 = -72 + 36

Reorder the terms:

36 + -12x + x2 = -72 + 36

Combine like terms: -72 + 36 = -36

36 + -12x + x2 = -36

Factor a perfect square on the left side:

(x + -6)(x + -6) = -36

Can't calculate square root of the right side.

The solution to this equation could not be determined.

MARK BRAINLIEST PLSSS