Mathematics, 27.05.2021 09:10 hussain52

Please help. How do you find cosine, sine, cosecant and secant with this triangle?

Answers: 1

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Answer from: adwinajames

Hi there! You have to remember these 6 basic Trigonometric Ratios which are:

sine (sin) = opposite/hypotenusecosine (cos) = adjacent/hypotenusetangent (tan) = opposite/adjacentcosecant (cosec/csc) = hypotenuse/oppositesecant (sec) = hypotenuse/adjacentcotangent (cot) = adjacent/oppositecosecant is the reciprocal of sinesecant is the reciprocal of cosinecotangent is the reciprocal of tangent

Back to the question. Assuming that the question asks you to find the cosine, sine, cosecant and secant of angle theta.

What we have now are:

Trigonometric RatioAdjacent = 12Opposite = 10

Looks like we are missing the hypotenuse. Do you remember the Pythagorean Theorem? Recall it!

a²+b² = c²

Define that c-term is the hypotenuse. a-term and b-term can be defined as adjacent or opposite

Since we know the value of adjacent and opposite, we can use the formula to find the hypotenuse.

10²+12² = c²100+144 = c²244 = c²

Thus, the hypotenuse is:

$\large \boxed{c = 2 \sqrt{61} }$

Now that we know all lengths of the triangle, we can find the ratio. Recall Trigonometric Ratio above! Therefore, the answers are:

cosine (cosθ) = adjacent/hypotenuse = 12/(2√61) = 6/√61 = (6√61) / 61sine (sinθ) = opposite/hypotenuse = 10/(2√61) = 5/√61 = (5√61) / 61cosecant (cscθ) is reciprocal of sine (sinθ). Hence, cscθ = (2√61/10) = √61/5secant (secθ) is reciprocal of cosine (cosθ). Hence, secθ = (2√61)/12 = √61/6

Questions can be asked through comment.

Furthermore, we can use Trigonometric Identity to find the hypotenuse instead of Pythagorean Theorem.

Hope this helps, and Happy Learning! :)

Answer from: Quest

There is no association.
Which statement best describes the association between variable x and variable y? perfect negative

Answer from: Quest

see attached

step-by-step explanation:

given the function as;

$f(x)=2x^3-7x^2+2x+3$

write the equation replacing f(x) with y

$y=2x^3-7x^2+2x+3$

form and fill a table containing values of y with corresponding values of x

you can take a range for values of x as -3≤x≤3

solving for x=-3

$f(-3)=2*-3^3-7*-3^2+2*-3+3=2*-27-63+-6+3=-54-63-6+3y=-120$

for x=-2

$f(-2)=2*-2^3-7*-2^2+2*-2+3=2*-8-28+-4+3=-16-28-4+3=-45$

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values of x and obtain the following graph

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