7X+2=5X+12 how do i show my work for this??

Subtract 2 from each side=7X+2-2=5X+12-2

simplify=7X=5X+10

subtract 5x=7X-5X=5X+10-5X

simplify=2x=10

divide both sides by 2=2x/2=10/2

simplify=x=5

use symbolab for setbystep symbolab.com

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

16.9 times 2.85

step-by-step explanation: