The height h, in feet, that an arrow will reach 1 seconds after being shot directly upward is gyven by the formula h = 1121 - 162t^2 How high will the arrow be after 4 seconds?

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Talia took the bus from her home to the bank and then walked back to her home along the same route. the bus traveled at an average speed of 40 km/h and she walked at an average speed of 5 km/h. to determine the time, x, that it took talia to walk home, she used the equation 40(0.9 – x) = 5x. the time of trip 2 is hours. the distance of trip 1 is km.

Match each equation to the ordered pair that represents one of its solutions. 3x + 2y = 6 -5x + y = -10 x ? 4y = 8 -6x ? 5y = 30 ordered pair equation (0, -6) arrowboth (0, 3) arrowboth (4, -1) arrowboth (1, -5) arrowboth reset next unit 2 - pretest