Suppose the heights of men in a particular country have a normal distribution with a mean of 70 inches and a standard deviation of 3 inche a) What percentage of men would have a height between 66 and 75 inches? Give answer to the nearest whole percent.
b) If a random group of 350 men in this country were measured, how many of them would we expect to be between 66 and 75 inches?
c) Below what height would we expect 2.5% of all men to be?
d)What would it mean if someone's height is 3 standard deviations from the mean?

i can you with this sweetie!

step-by-step explanation:

step-by-step explanation:

; fx

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt