A hunter is at a distance of 50 m south of a nest. He uses a pair of binoculars to observe an eagle flying at 10 m/s towards the nest in a straight line. At what rate is the hunter rotating the pair of binoculars when the eagle is 10 m away from the nest? A.
0.137 rad/sec.
B.
0.141 rad/sec.
C.
0.165 rad/sec.
D.
0.192 rad/sec.

step-by-step explanation:

from the graph attached below:

domain of graph is the value of x for which the given function profit function p(x) is defined.

(a) the domain represents the number of years for which the outlet will earn a profit.

range of profit function defines the lowest to highest value of profit earned.

(b) the range of this function is (0 , 160 ). for this function, the range represents the outlet's profit earned.

8.75

how-to:

first, we need to find what we have to work with.

since i know that we have 7 (years) and 0.8 (inches), we can use these to solve and find the equation!

secondly, what you want to do, is see that we need to know how much growth out of the 0.8 inches he got in only 1 year, instead of 7 years.

let's try to divide.

7 ÷ 0.8 = 8.75