A marble started with 0.0018 J of Potential Energy and at some point later it has only 0.0011 J of Potential Energy. How much Kinetic Energy does the marble have?

the Kinetic Energy of the marble at the later point is 0.0007 J

Step-by-step explanation:

Given;

initial potential energy of the marble, P.E₁ = 0.0018 J

final potential energy of the marble, P.E₂ = 0.0011 J

At the initial starting point, the total mechanical energy is;

M.E = K.E + P.E

at the initial starting point, velocity = 0

M.E = 0 + P.E

M.E = P.E = 0.0018 J

At some point later, the total mechanical energy is;

M.E = P.E + K.E

0.0018 J = 0.0011 J + K.E

0.0018 J - 0.0011 J = K.E

0.0007 J = K.E

Therefore, the Kinetic Energy of the marble at the later point is 0.0007 J

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)

answer is because 4×10=40

and 98×4= is 392

40,392