Azul spun a tri-color spinner twice. What is the probability that the spinner landed on the colors blue and green in any order? BB, BG, BY, GB, GG, GY, YB, YG, YY 2 ON 3 Acvate Win Gettings to​

The Probability that the spinner landed on the colors blue and green in any order = 2/9

Step-by-step explanation:

Given - Azul spun a tri-color spinner twice.

To find - What is the probability that the spinner landed on the colors blue and green in any order?

Solution -

Given that,

A tri-color spinner spun twice

So,

The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}

⇒n(S) = 9

Now,

Let A be an event that the spinner landed on the colors blue and green

So,

A = {BG, GB}

⇒n(A) = 2

Now,

Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)

         = 2 ÷ 9

∴ we get

The Probability that the spinner landed on the colors blue and green in any order = 2/9

for the free

< < < emily> > >

the correct answer is b.

this is because an open circle means < or > & since the line goes left it is < -3.

the next one has a filled circle so it can only be ≥ or ≤ and since the line goes right from 1 it is ≥ 1

hope that