Students at Elon University were surveyed and the average commute distance to campus is 0.5 mile. Assume the population standard deviation is 0.1 mile. Please construct a 90% confidence interval for the population mean. a. [0.472, 0.528]
b. [0.479, 0.521)
c. [0.463, 0.534]
d. [0.476, 0.524]

The 90% confidence interval for the population mean is , in which n is the number of students surveyed.

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

That is z with a pvalue of , so Z = 1.645.

Now, find the margin of error M as such

In which is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M, while the upper end is M added to the sample mean of 0.5. Thus, the confidence interval is of:

The 90% confidence interval for the population mean is , in which n is the number of students surveyed.

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.