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D; x -y = 22

3x + 2y = 246

Step-by-step explanation:

Let us have the bigger number as x and the smaller as y

The difference between the two is 22

Thus, we have it that;

x - y = 22

twice the smaller number; 2(y) added to thrice the larger 3(x) equals 246

3x + 2y = 246

So we have the two equations as;

x -y = 22

3x + 2y = 246

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: