PLEASE HELP Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find the values of the trigonometric functions.

sin(θ) =

cos(θ) =

tan(θ) =

csc(θ) =

sec(θ) =

cot(θ) =

Answers:

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Explanation:

Refer to the diagram below. The point (8,-15) is in quadrant 4, which is the southeast quadrant. A right triangle forms where the hypotenuse goes from the origin to the terminal point in question. After applying the pythagorean theorem, the hypotenuse is 17 units long.

Opposite the reference angle θ, greek letter theta, the side is -15. Usually negative lengths are not allowed and don't make any sense; however, I'm making this negative to ensure that sin(θ) ends up negative. This will help with other trig ratios as well.

So,

sin(angle) = opposite/hypotenuse

sin(θ) = -15/17

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The cosine ratio will involve the adjacent and hypotenuse

cos(angle) = adjacent/hypotenuse

cos(θ) = 8/17

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Tangent is opposite over adjacent

tan(angle) = opposite/adjacent

tan(θ) = -15/8

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The functions csc(θ), sec(θ), and cot(θ) are the functions cosecant, secant, and cotangent in that order.

They represent the reciprocal of sine, cosine, and tangent in that order as well.

Eg: sec(θ) is the reciprocal of cos(θ)

This means,

As an alternative, you could also say

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Here's a list of formulas that you can write down on a reference sheet

where h is the hypotenuse and h = sqrt(x^2+y^2). Notice that something like tan = y/x is the reciprocal of cot = x/y. The x and y refers to the coordinates of the terminal point given to you. Make sure to reduce all fractions as much as possible. In our case, none of the fractions can be reduced any further.

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.

ddd

step-by-step explanation: