How would someone Algebraically determine X-Y intercepts?

y-int:  -6

x-int: -2/5 and 3

Step-by-step explanation:

you can find the y-intercept by substituting zero in for every 'x' in the equation;

y = 5(0) - 13(0) - 6

y = -6

to find the x-intercept(s), factor the trinomial by trying to find a pair of factors that multiply to 6 and add to -13; the factors that work are:

(5x + 2)(x - 3)

now set each factor equal to zero and solve for 'x':

5x + 2 = 0

5x = -2

x = -2/5

x - 3 = 0

x = 3

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