Find the product of
(−9−11i) and its conjugate.

202

Step-by-step explanation:

First, we can find the conjugate of (-9 -11i)

Given a complex number a + bi, the conjugate would be a - bi.

So, the conjugate of -9 -11i is -9 + 11i.

Now, we multiply!

(-9-11i)(-9+11i)

This resembles the special product (a+b)(a-b) which multiplies out to a^2 - b^2

To apply this we subtract the square of the second number from the first.

(-9)^2 - (11i)^2

81 - 121i^2

i^2 is -1, so we can substitute it in:

81 + 121 = 202

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step-by-step explanation:

bull

step-by-step explanation: