A group of friends wants to go to the amusement park. They have no more than $195 to spend on parking and admission. Parking is $8.50, and tickets cost $33 per person, including tax. What is the maximum number of people who can go to the amusement park?

17.75x + 5.25  165

x  9

Step-by-step explanation:

The total cost can be represented by 17.75x + 5.25, where x is the number of people.

They can only spend a maximum of $165, so a less than or equal sign has to be used.

The inequality will be 17.75x + 5.25  165

Now, solve for x:

17.75x + 5.25  165

17.75x  159.75

x  9

So, x  9 is the answer, meaning 9 people or less can go to the amusement park.

Please mark brainliest

4

Step-by-step explanation:

Based on the information given in the question, the inequality which can be used to determine x, the number of people who can go to the amusement park will be:

8 + 23(x) ≤ 100

8 + 23x ≤ 100

23x ≤ 100 - 8

23x ≤ 92

x ≤ 92/23

x ≤ 4

The number of people that can go to the amusement park will be at most 4

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

a.) list the factors of 40.

1/2/4/5/8/10/20/40

b.) list the factors of 40 that represent the number of cans that could be on each shelf.

5

c.) how many different arrangements of cans are possible?

just one because if you put more on one shelf you will go way over 40 and the cabinet will probably break.

d.) what are the possible arrangements of the cans?

put 5 cans on each self to reach 40 cans in total.

e.) which arrangement uses all the shelves?

5 because you can put 5 cans on each shelf, and since there are 8 shelfs you are equally going to get 40 cans.