Which ordered pair is a solution to the inequality
y ≥ 4x-5

(3,0) (3,4) (1,1) (2,1)

(1, 1)

Step-by-step explanation:

in the order pair you have (x, y) so if is ( 3, 0) it means is ( x=3, y=0)

substitute in the inequality those x, and y values and see if it checks

y ≥ 4x-5

for ( 3, 0) is 0 ≥ 4*3-5 false

for ( 3,4)  is 4 ≥ 4*3-5 false

for (1,1) is 1 ≥ 4*1-5 true because 1 ≥ -1

for (2, 1) is 1 ≥ 4*2-5 false

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .