A population of emperor penguins has a mean weight of 77 pounds with a standard deviation of 16 pounds. What would be the standard deviation of sample means taken from this population with a sample size of 50?

2.263

Step-by-step explanation:

standard deviation of sample means = s/\sqrt{n}

Given

Standard deviation s = 16pounds

Sample size n = 50

Substituting

standard deviation of sample means = 16/\sqrt{50}

standard deviation of sample means = 16/7.071

standard deviation of sample means = 2.263

Hence the standard deviation of sample means taken from this population with a sample size of 50 is 2.263

the answer is 4.8 units on e2020.