Mathematics, 21.05.2021 17:30 lilay30

The average teaching salary in Georgia is $48,553 per year. The school districts in the metro Atlanta area boast that they pay more. A company that is running a career fair decides to take a random sample of 228 teachers from the metro Atlanta area and record their salaries. The sample mean is $49,021, with a standard deviation of $3,127. Required:
Do the data provide statistically significant evidence at the 0.06 kevel that the average teaching stay in the metro Atlanta area is greater than the state average?

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Answers

The p-value of the test is 0.0119 < 0.06, which means that the data provides statistically significant evidence at the 0.06 level that the average teaching stay in the metro Atlanta area is greater than the state average.

Step-by-step explanation:

The average teaching salary in Georgia is $48,553 per year. The school districts in the metro Atlanta area boast that they pay more.

At the null hypothesis, we test if they pay the average, that is:

$H_0: \mu = 48553$

At the alternate hypothesis, we test if they pay more, that is:

$H_1: \mu 48553$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

48553 is tested at the null hypothesis:

This means that $\mu = 48553$

Sample of 228 teachers from the metro Atlanta area and record their salaries. The sample mean is $49,021, with a standard deviation of $3,127.

This means that $n = 228, X = 49021, \sigma = 3127$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{49021 - 48553}{\frac{3127}{\sqrt{228}}}$

z = 2.26

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 49021, which is 1 subtracted by the p-value of z = 2.26.

Looking at the z-table, z = 2.26 has a p-value of 0.9881

1 - 0.9881 = 0.0119

Answer from: Quest

$a_1 = 1$ , and

$a_{n+1} = a_n + (n + 1)$ for $n \ge 1$

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote $a_1 = 1$ , $a_2 = 3$ , $a_3 = 6$ , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from $a_1 = 1$ , to get to $a_2 = 3$ , we add $2(=1+1)$