WILL GIVE BRAINLIEST Q1) ABCD is a square. A is the point (-2,0) and C is the point (6,4). AC and BD are diagonals of the square, which intersect at M.
a) Find the coordinates of M, B and D.
b) Find the area of ABCD.

9514 1404 393

  a)  M(2,2), B(4, -2), D(0, 6)

  b)  40

Step-by-step explanation:

a) The midpoint of AC is the average of the endpoint coordinates.

  M = (A +C)/2

  M = ((-2, 0) +(6, 4))/2 = (4, 4)/2

  M = (2, 2)

There are several ways to find points B and D. One of them is to rotate points A and C 90° about M. The 90° CCW rotation transformation about the origin is ...

  (x, y) ⇒ (-y, x)

About the point (2, 2), the transformation would be ...

  (x, y) ⇒ (-(y -2)+2, (x -2)+2) = (4 -y, x)

Rotating point A 90° to get point B, we have ...

  B = (4 -0, -2)

  B = (4, -2)

And rotating C to get point D, we have ...

  D = (4 -4, 6)

  D = (0, 6)

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b) The area of the square is half the square of the diagonal. The square of the diagonal can be found using the distance formula ...

  d² = AC² = (6-(-2))² +(4 -0)² = 64 +16 = 80

Then the area is ...

  area = AC²/2 = 80/2

  area = 40 . . . . square units

use distributive property on all like terms and change your signs if you have a double negative or if you have positive/negative