Melon, Kiwi, Lupert, & Corn know that a triangle with sides of 3 units, 4 units, and 5 units is a right triangle. Their teacher asks them to find another right triangle. Lupert triples the side lengths of the 3, 4, 5 triangle to get a triangle of 9, 12, 15. Melon adds three to the side lengths of the 3, 4, 5 triangle to get a triangle of 6, 7, 8. Kiwi doubles the side lengths of the 3, 4, 5 triangle to get a triangle of 6, 8, 10. Corn adds four to the side lengths of the 3, 4, 5 triangle to get a triangle of 7, 8, 9. Who correctly made a right triangle? Explain or show how you know.

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct

1. supplementary angles

2. acd and bcd

step-by-step explanation:

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7