Consider the following equation.
2^(x)+3=3^(-x)
If the equation is solved using successive approximation, match the value of x to the following iterations.

9514 1404 393

  no iterations shown; the root is approximately -1.12911

Step-by-step explanation:

If your method of successive approximation is the Bisection Method, and if your initial interval is [-2, -1], then successive values of x used for reducing the interval are ...

  -1.5, -1.25, -1.125, -1.1875, -1.15625

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If your method of successive approximation is Newton's method, and if your initial guess is -1.5, then successive values of x will be ...

  -1.1905079, -1.1309053, -1.1291151, -1.1291135

Another iteration confirms this last value is accurate to 8 significant figures.

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