A circle is centered about the point (2, 0). The point (0, 1) is on the circle. Which statement proves that the point (4, 1) is also on the circle?

Step-by-step explanation:

the circle is at the origin and (0,4) is a point on the circle then the radius of the circle is:

r^2=0^2+4^2

r^2=16

r=4

so we can check that the other point is four units from the origin and thus also on the circle...

d^2=2^2+6^2

d^2=4+36

d^2=40

since d^2>r^2, (2,6) is outside the circle

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

27/4x^6 y^8

step-by-step explanation:

4(3x^2y^4)^3 (2x^3y^5)^4

=

108x^6 y^12 /16x^12 y^20

=

108 /16x^6 y^8

=

27 /4x^6 y^8