The scores on a test are normally distributed, with a mean of 82 and standard deviation of 8. What percent of scores are greater than 90? Explain your answer.

14.64%

Step-by-step explanation:

P(90<X<100) = normalcdf(90,100,82,8) = 0.1464308262 ≈ 0.1464 ≈ 14.64%

Therefore, about 14.64% of the scores are greater than 90.

idk wbu

step-by-step explanation:

answer is because 4×10=40

and 98×4= is 392

40,392