PLEASE HELP WILL GIVE BRAINLIEST. Which of the following statments is true about the equation shown? Mark all that are true. t (x) = (x-5)^2 + 7. a
the function is quadratic
b
the function will produce a line with a positive slope when graphed
c
the function will produce a concave up parabola when graphed
d
the vertex will be at (7, -5)

a and c

Step-by-step explanation:

The equation of a quadratic in vertex form is

f(x) = a (x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

f(x) = (x - 5)² + 7 ← is in vertex form

Thus the function is quadratic → a

• If a > 0 then the grapg will open upwards

• If a < 0 then the graph will open downwards

Here a = 1 > 0 then graph will open upwards → c

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: