What is the probability of the spinner landing on E for a first spin and either C or D for a second spin?

We can't see the image of the spinner. So let's solve this in a general way.

Let's assume that the probability of landing on E is:

P(E)

And the same for all the letters, we will have:

P(A), P(B), P(C), P(D).

Then, the probability of the spinner landing on E for the first spin is just P(E).

Now, the probability of landing on either C or D is: P(C) + P(D)

The joint probability, thus, the probability of both events happening is:

P = P(E)*(P(C) + P(D))

Now, if each letter has the same probability (and we have 5 of them)

Then:

P(E) = 0.2

P(C) = 0.2

P(D) = 0.2

Replacing that in the equation we would get:

P = 0.2*(0.2 + 0.2) = 0.2*0.4 = 0.08

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13

d no solution

step-by-step explanation: