Damian has a bag that contains strawberry chews, cherry chews, and peach chews. He performs an experiment. Damian randomly removes a chew from the bag, records the result, and returns the chew to the bag. Damian performs the experiment 48 times. The results are shown below: A strawberry chew was selected 16 times. A cherry chew was selected 10 times. A peach chew was selected 22 times. Based on these results, express the probability that the next chew Damian removes from the bag will be cherry or peach as a fraction in simplest form.

2/3

Step-by-step explanation:

answer:  

123455421

step-by-step explanation: easy

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.