The area of the rectangle is 40% larger than the area of the triangle. What is the length ,L, of the rectangle?

10 units

Step-by-step explanation:

Area of the triangle (A') = 1/2bh

A' = 1/2bh............ Equation 1

Where b = base of the triangle, h = height of the triangle

From the diagram,

Given: b = 12.5 unit, h = 4 unit

Substitute into equation 1

A' = 1/2(12.5)(4)

A' = 25 squared unit.

Also,

Area of the rectangle (A) = Lenght(L)×width(w)

A = Lw............ Equation 2

From the question,

If the area of the rectangle is 40% larger than the area of the triangle

Therefore,

A = 1.4A'

A = 1.4(25)

A = 35 squared unit.

Also given: w = 3 = 7/2

Substitute into equation 2

35 = L×7/2

7L = 35×2

7L = 70

L = 70/7

L = 10 units

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints