Mathematics, 19.05.2021 18:40 TheOneandOnly003
We plan to choose a random sample of college students in Norman (OK) and Lubbock (TX) to examine how they spent their time on Friday evenings during the pandemic (from early April 2020 to late December 2020). Consider the population variable below: Cost of food, drink, and entertainment on a Friday evening. Let us assume that the population standard deviation is $12.5. Also, let us assume that we are willing to accept only a $1.5 margin of errors in our estimations. Level of confidence being set at 95%, how many observations do we need in order to estimate the population mean for the above cost?
Answers: 1
Mathematics, 21.06.2019 15:40, FailingstudentXD
Each of the walls of a room with square dimensions has been built with two pieces of sheetrock, a smaller one and a larger one. the length of all the smaller ones is the same and is stored in the variable small. similarly, the length of all the larger ones is the same and is stored in the variable large. write a single expression whose value is the total area of this room. do not use any method invocations.
Answers: 1
Mathematics, 22.06.2019 01:10, tashatyron24pejls0
|z| > (1/2) {-1/2, 1/2} {z|(-1/2) < z < (1/2)} {z|z < (-1/2) ∪ z > (1/2)}
Answers: 3
Mathematics, 22.06.2019 03:20, mehnamejet92
Given a normal distribution with µ =50 and σ =4, what is the probability that 5% of the values are less than what x values? between what two x values (symmetrically distributed around the mean) are 95 % of the values? instructions: show all your work as to how you have reached your answer. don’t simply state the results. show graphs where necessary.
Answers: 3
We plan to choose a random sample of college students in Norman (OK) and Lubbock (TX) to examine how...
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