Solve for .
2r +7= 16
r

Step-by-step explanation:

=> 2r + 7 = 16

=> 2r = 16 - 7

=> r = 9/2

=> r = 4.5

r= 1/2

Step-by-step explanation:

Subtract  7   from both sides of the equation

2 + 7 = 1 6

2 + 7 − 7 = 1 6 − 7

Simplify

2 = 1 6 − 7

Subtract  16r  from both sides of the equation

2 = 1 6 − 7

2 − 1 6 = 1 6 − 7 − 1 6

Simplify

-14r= -7

Divide both sides of the equation by the same term

− 1 4 = − 7

-14r=-7

− 1 4 − 1 4

Simplify

r= 1/2

answer: 1 and 3

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.