11.) At liftoff, the space shuttle Discovery has a constant acceleration of 16.4 feet per second squared and an initial velocity of 1341 feet per second due to the rotation of Earth. The distance Discovery has traveled t seconds after liftoff is
given by the equation d(t) = 1341t + 8.2t2. How long after liftoff has Discovery traveled 40,000 feet? Round your answer
to the nearest tenth.