HELP ME PLEASE A Diginacci sequence is created as follows.
• The first two terms are any positive whole numbers.
• Each of the remaining terms is the sum of the digits of the previous
two terms.
For example, starting with 5 and 8 the Diginacci sequence is
5, 8, 13, 12, 7, 10,. . .
The calculations for this example are
5 + 8 = 13, 8 + 1 + 3 = 12, 1+ 3 +1+ 2 = 7, 1 + 2 + 7 = 10.

1. Find, with explanation, two starting terms for a Diginacci sequence
so that its 2021st term is 11.

2. Find, with explanation, a Diginacci sequence that has no term equal
to 11.

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation:

16.80 times .20= 3.36

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

this is a good question! i'll do some research and come back when i have the answer!