Step 1: Draw an arc centered at point Q that intersects both sides of ∠PQR∠PQR. Step 2: Draw an arc centered at point T. Step 3: With the same radius draw an arc centered at point U. Step 4: Draw QS−→QS→.   QS−→QS→ is the of∠PQR PLEASE HELP ME. ANSWER THIS WITH A PICTURE SHOWING YOUR WORK AND STEPS‼️​

M? aoc=96 ? space, m, angle, a, o, c, equals, 96, degree \qquad m \angle boc = 8x - 67^\circm? boc=8x? 67 ? space, m, angle, b, o, c, equals, 8, x, minus, 67, degree \qquad m \angle aob = 9x - 75^\circm? aob=9x? 75 ? space, m, angle, a, o, b, equals, 9, x, minus, 75, degree find m\angle bocm? bocm, angle, b, o, c: