One base of a trapezoid is 4 in more than twice the length of the second base. The height of the trapezoid is 2 in less than the second base. If the area of the trapezoid is 4 in^2, find the dimensions of the trapezoid.

Step-by-step explanation:

Let us represent

1st base of trapezoid = a

2nd bass of trapezoid = b

Height of trapezoid = c

One base of a trapezoid is 4 in more than twice the length of the second base.

a = 2b

The height of the trapezoid is 2 in less than the second base.

h = b - 2

Area of a trapezoid = 1/2(a + b)h

If the area of the trapezoid is 4 in^2

Substituting

4 = 1/2(2b + b)b - 2

4 = 1/2(3b)b - 2

Cross Multiples

4 × 2 = (3b)b - 2

6 = 3b² - 6b

Hence,

3b² - 6b - 6

find the dimensions of the trapezoid.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?