What is the radius of a circle with the equation x^2+y^2-14x+10=250

radius is 17

Step-by-step explanation:

Use "completing the square" to rewrite the given equation in standard form for a circle centered at (h, k) with radius r:

x^2+y^2-14x+10=250 becomes:

x^2 - 14x + y^2 = 240 after grouping x terms and  y terms separately.

Completing the square, once for x and once for y, results in:

x^2 - 14x + 49 - 49 + y^2 = 240.

Rewriting x^2 - 14x + 49 as the square of the binomial x - 7 results in:

(x - 7)^2 + y^2 = 289 = 17^2

From this we recognize that the center is at (7, 0) and the radius is 17.

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

idk

step-by-step explanation: