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9514 1404 393

  16 miles

Step-by-step explanation:

The problem can be modeled by a right triangle with one angle of 7° and the side opposite being 10,000 ft. The distance needed is the hypotenuse of the triangle, so the relevant trig relation is ...

  Sin = Opposite/Hypotenuse

  Hypotenuse = Opposite/Sin

  air distance = (10,000 ft)/sin(7°) ≈ 82,055 ft

At 5,280 ft per mile, that is ...

  (82,055 ft)/(5,280 ft/mi) ≈ 15.54 mi

The plane's air distance to the airport is about 16 miles.

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).