The acceleration of a vehicle, in mph per second, is given by a(t) = –6. If the velocity of the vehicle is 60 mph at t = 2 seconds, the velocity at t = 4 seconds is

4

step-by-step explanation:

not sure but it may be b, as i said i'm not sure.

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %