A rectangle has the perimeter of 116 cm and its length is 1cm more than twice its width​

Find the dimensions of a rectangle given that its perimeter is 116

 cm and its length is 1

 cm more than twice its width.

Set up your solution using the variables L

 for the length, W

 for the width, and P

 for the perimeter. 

Part a: Using the definition of perimeter, what is an equation for P

 in terms of L

 and W

.

Part b: You also have to write an equation for L in terms of W

 in terms of W

.

Solve the equations from parts a and b.

Part c: The length is   cm.

Part d: The width is   cm.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

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step-by-step explanation: