If f(x) = х2 – 2x and g(x) = 6х +4, for which vаluе оf x does (f+g)(x) = 0?

x²+4x+4=0

(x+2)(x+2)=0

x= -2

f(g(x))=0

f(6x+4)=0

f(0)=0

x=-4/6

i did it in to step because i didnt understand what you mean we you write (f+g)(x)

but probably the first answer is the correct one

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

i dont know sorry

step-by-step explanation: