What is the probabilty of drawing a diamond from a standard deck of cards on a second draw, give that a diamond was drawn on the first draw and not replaced? 12/51
1/52
1/52
13/52

need help too

Step-by-step explanation:

Explanation:

"Given that a diamond was drawn on the first draw and not replaced" means we know 100% that there are P = 13 - 1 = 12 diamonds left out of Q = 52-1 = 51 cards overall.

The probability of picking another diamond card is therefore P/Q = 12/51

This only works if the card is not replaced. If the card is replaced, then the probability would be 13/52 = 1/4.

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube

sweetheart, there isn't a cube below.