A1 = 7; an = a(n-1) + 6
Find the first 6 terms of the sequence.

Step-by-step explanation:

you really need help with that ? it is all already given in the problem description. you only need to do the 6 little calculations (anyways adding 6). what is the problem ?

a1 = 7

a2 = a1 + 6 = well ? ... ... ... 13, of course

a3 = a2 + 6 = 13 + 6 = w ?

a4 = a3 + 6 = 13 + 6 + 6 = w ?

a5 = a4 + 6 = 13 + 6 + 6 + 6 =

a6 = a5 + 6 = 13 + 6 + 6 + 6 + 6 =

I am really not doing your very basic and just "mechanical" work of doing simple calculations in your head or on your calculator.

I help you, when you have a problem understanding the issue, but not when you ask me to do your pure "mechanical" job that every elementary school student can do easily.

to help with the understanding, such a sequence (using this example) can then be described and every element calculated by

a(n) = a(1) + 6*(n-1)

so, for example

a20 = 7 + 6*19 = 121

so, and now that you truly understand the concept, just use your calculator (if you truly cannot do that in your head) and do your job.

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)